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csc-2019-x-sec-5-x-tan-2-x-dx-




Question Number 60938 by aliesam last updated on 27/May/19
∫((csc^(2019) (x))/(sec^5 (x))) tan^2 (x) dx
csc2019(x)sec5(x)tan2(x)dx
Commented by Prithwish sen last updated on 27/May/19
∫((cos^3 x)/(sin^(2017) x))dx =∫(((1−sin^2 x)cosx)/(sin^(2017) x)) dx  put sinx = v  then cosx dx =dv  =∫(((1−v^2 )dv)/v^(2017) )  =∫(v^(−2017) −v^(−2015) ) dv
cos3xsin2017xdx=(1sin2x)cosxsin2017xdxputsinx=vthencosxdx=dv=(1v2)dvv2017=(v2017v2015)dv

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