csc10-3-sec10-

Question Number 166718 by mathlove last updated on 26/Feb/22

c s c 10 - \sqrt{3} s e c 10 = ?

Commented by cortano1 last updated on 26/Feb/22

\frac{1}{\sin 10 °} - \frac{\sqrt{3}}{\cos 10 °} = \frac{\cos 10 ° - \sqrt{3} \sin 10 °}{\frac{1}{2} \sin 20 °}

= \frac{2 (2) (\frac{1}{2} \cos 10 ° - \frac{\sqrt{3}}{2} \sin 10 °)}{\sin 20 °}

= \frac{4 (\cos 60 ° \cos 10 ° - \sin 60 ° \sin 10 °)}{\sin 20 °}

= 4