cx-b-2-2x-cx-2b-2-4x-cx-2-4b-2-8x-dx-

Question Number 185837 by test1234 last updated on 28/Jan/23

\int \frac{c x + b^{2}}{2 x} - \frac{c x + 2 b^{2}}{4 x} + \frac{{(c x)}^{2} + 4 b^{2}}{8 x} d x = ?

Commented by MJS_new last updated on 28/Jan/23

seriously ?

= \frac{c^{2}}{8} \int x d x + \frac{c}{4} \int d x + \frac{b^{2}}{2} \int \frac{d x}{x} =

= \frac{c^{2}}{16} x^{2} + \frac{c}{4} x + \frac{b^{2}}{2} \ln ∣ x ∣ + C

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