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d-2-y-dx-2-4-dy-dx-3-cosec-

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Question Number 125664 by fajri last updated on 12/Dec/20
(d^2 y/dx^2 ) + 4(dy/dx) = 3 cosec θ
$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:+\:\mathrm{4}\frac{{dy}}{{dx}}\:\:=\:\mathrm{3}\:{cosec}\:\theta \\ $$$$ \\ $$

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