Question Number 118813 by john santu last updated on 19/Oct/20
$$\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }\:−\mathrm{4}{x}\:\frac{{dy}}{{dx}}\:+\:{y}\left(\mathrm{3}{x}^{\mathrm{2}} −\mathrm{2}\right)=\:\mathrm{0}\: \\ $$
Answered by bemath last updated on 20/Oct/20