Question Number 87116 by lémùst last updated on 02/Apr/20
$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }+{x}^{\mathrm{2}} {y}=\mathrm{0} \\ $$
Answered by redmiiuser last updated on 03/Apr/20
$$\frac{{y}^{\mathrm{2}} }{\mathrm{2}}+\frac{{x}^{\mathrm{4}} .{y}}{\mathrm{12}}=\mathrm{0} \\ $$