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d-2-y-dx-2-x-2-y-0-




Question Number 56890 by Ismael002 last updated on 25/Mar/19
d^2 y/dx^2 =x^2 y=0
$${d}^{\mathrm{2}} {y}/{dx}^{\mathrm{2}} ={x}^{\mathrm{2}} {y}=\mathrm{0} \\ $$

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