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d-2-y-dx-2-ytan-x-e-x-y-0-1-y-0-0-




Question Number 163113 by Lordose last updated on 03/Jan/22
(d^2 y/dx^2 ) + ytan(x) = e^x   y(0) = 1, y′(0) = 0
$$\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:+\:\mathrm{ytan}\left(\mathrm{x}\right)\:=\:\mathrm{e}^{\mathrm{x}} \:\:\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{1},\:\mathrm{y}'\left(\mathrm{0}\right)\:=\:\mathrm{0} \\ $$

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