d-dx-ln-x-1-

Question Number 26947 by prakash jain last updated on 31/Dec/17

\frac{d}{d x} \ln (Γ (x + 1)) = ?

Commented by abdo imad last updated on 31/Dec/17

w e k n o w t h a t Γ (x + 1) = x Γ (x) w i t h x > 0

\Rightarrow l n (Γ (x + 1)) = l n x + l n (Γ (x))

\Rightarrow \frac{d}{d x} l n (Γ (x + 1)) = \frac{1}{x} + \frac{Γ^{,} (x)}{Γ (x)} .

Answered by Femmy last updated on 31/Dec/17

ans

\ln Γ + \ln (x + 1)

1 / Γ + 1 / (x + 1)

Commented by prakash jain last updated on 31/Dec/17

Actually I meant Γ as gamma function

Commented by Femmy last updated on 31/Dec/17

okay sir

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