Question Number 92976 by frc2crc last updated on 10/May/20
$${define} \\ $$$$\Delta_{{n}} =\frac{{n}\left(\mathrm{1}+{n}\right)}{\mathrm{2}} \\ $$$${find}\:{a}\:{closer}\:{form}\:{for} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\Delta_{{n}} ^{{m}} } \\ $$
Answered by john santu last updated on 10/May/20
$$\mathrm{what}\:\Delta_{\mathrm{n}} ^{\mathrm{m}} \:?\: \\ $$
Commented by frc2crc last updated on 10/May/20
$$\Delta_{{n}} =\frac{{n}^{\mathrm{2}} +{n}}{\mathrm{2}}\Rrightarrow\Delta_{{n}} ^{{m}} =\frac{\left({n}^{\mathrm{2}} +{n}\right)^{{m}} }{\mathrm{2}^{{m}} } \\ $$
Commented by frc2crc last updated on 10/May/20
$${i}\:{used}\:{this}\:{definition} \\ $$