Question Number 165815 by SANOGO last updated on 08/Feb/22
$${deteminer}\:{l}'{expression}\:{de}\:{g}\left({x}\right) \\ $$$${g}\left({x}\right)=\underset{{n}=\mathrm{1}} {\overset{+{oo}} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{{n}}{x}^{{n}} \\ $$
Answered by puissant last updated on 08/Feb/22
$${g}\left({x}\right)=−{ln}\left(\mathrm{1}+{x}\right)={ln}\left(\frac{\mathrm{1}}{\mathrm{1}+{x}}\right).. \\ $$
Commented by moubiel last updated on 17/Mar/22
cool