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determinant-x-7-9-8-x-determinant-7-0-3-5-x-6-3-5-x-9-




Question Number 90316 by M±th+et£s last updated on 22/Apr/20
 determinant ((x,7),(9,(8−x)))= determinant ((7,0,(−3)),((−5),x,(−6)),((−3),(−5),(x−9)))
|x798x|=|7035x635x9|
Commented by john santu last updated on 23/Apr/20
8x−x^2 −63 = 7(x^2 −9x−30)−  3(25+3x)  −x^2 +8x−63=7x^2 −63x−210−75−9x  −x^2 +8x−63=7x^2 −72x−285  8x^2 −80x−222=0  4x^2 −40x−111=0  x = ((40 ± (√(40^2 +444)))/8)
8xx263=7(x29x30)3(25+3x)x2+8x63=7x263x210759xx2+8x63=7x272x2858x280x222=04x240x111=0x=40±402+4448
Commented by M±th+et£s last updated on 23/Apr/20
sir i think its 8x^2 −80x−222 and  thank you now ican do it with my self
sirithinkits8x280x222andthankyounowicandoitwithmyself
Answered by M±th+et£s last updated on 23/Apr/20
Commented by john santu last updated on 23/Apr/20
yes. good
yes.good

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