Determinate-the-values-of-n-N-such-that-n-1-can-divise-2n-3-

Question Number 122648 by mathocean1 last updated on 18/Nov/20

D e t e r m i n a t e t h e v a l u e s o f n \in N

s u c h t h a t n - 1 c a n d i v i s e 2 n + 3

Answered by TANMAY PANACEA last updated on 18/Nov/20

2 n - 2 + 5 w h e n d e v i d e d b y n - 1

2 + \frac{5}{n - 1} n s h o u l d b e 6

Commented by mathocean1 last updated on 18/Nov/20

t h a n k y o u s i r

Answered by MJS_new last updated on 18/Nov/20

2 n + 3 = k (n - 1)

k = 2 + \frac{5}{n - 1}

\Rightarrow for n \in Z : n - 1 ∣ 5 \Rightarrow n \in {- 4, 0, 2, 6}

but n \in N \Rightarrow n \in {0, 2, 6}

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