Determine-the-total-translational-energy-of-two-litres-of-oxygen-gas-held-at-a-temperature-of-0-C-and-pressure-of-one-atmosphere-

Question Number 42131 by Necxx last updated on 18/Aug/18

D e t e r m i n e t h e t o t a l t r a n s l a t i o n a l

e n e r g y o f t w o l i t r e s o f o x y g e n g a s

h e l d a t a t e m p e r a t u r e o f 0 ° C a n d

p r e s s u r e o f o n e a t m o s p h e r e .

Commented by Necxx last updated on 19/Aug/18

p l e a s e h e l p

Answered by tanmay.chaudhury50@gmail.com last updated on 19/Aug/18

P V = n R T P = p r e s s u r e V = v o l u m e T = t e m p

n = \frac{P V}{R T} n = n u m b e r s o f m o l e

U = \frac{1}{2} N f K T U = t o t a l e n e r g y N = a v o g a d r o n u m b e r

f = d e g r e e s o f f r e e d o m N K = R

U = \frac{1}{2} R f T

f o r o x y g e n f = 3 t r a n s l a t i o n a l d e g r e e s o f f r r e d o m

e n e r g y p e r d e g r e e s o f f r e e d o m

\frac{U}{f} = \frac{1}{2} R T

s o r e q u i r e d t r a n s l a t i o n a l e n e r g y

= 3 n \times \frac{1}{2} \times R T

= 3 \times \frac{P V}{R T} \times \frac{1}{2} \times R T

= \frac{3}{2} (P V) = \frac{3}{2} \times 1.01 \times 10^{5} \times 2 \times 10^{- 3} = 3.03 \times 10^{2} J

p l s c h e c k \dots .

Commented by Necxx last updated on 20/Aug/18

o h \dots T h a n k s b o s s

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