Question Number 161750 by CM last updated on 22/Dec/21
$${differenciate}\:{x}\mathrm{sin}\:{x}\mathrm{cos}\:{x} \\ $$
Commented by cortano last updated on 22/Dec/21
$$\:{f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{2}}{x}\:\mathrm{sin}\:\mathrm{2}{x}\: \\ $$$$\:\frac{{df}}{{dx}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{sin}\:\mathrm{2}{x}+\mathrm{2}{x}\:\mathrm{cos}\:\mathrm{2}{x}\right) \\ $$$$\:\:\:\:\:\:\:\:\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin}\:\mathrm{2}{x}+{x}\:\mathrm{cos}\:\mathrm{2}{x} \\ $$$$ \\ $$
Commented by CM last updated on 22/Dec/21
$${Thank}\:{you}\: \\ $$