Question Number 161209 by CM last updated on 14/Dec/21
$${Differentiate}\:{y}={e}^{−{x}^{\mathrm{2}} } \\ $$
Commented by cortano last updated on 14/Dec/21
$$\:\Leftrightarrow\mathrm{ln}\:{y}=−{x}^{\mathrm{2}} \\ $$$$\Leftrightarrow\frac{{y}'}{{y}}\:=\:−\mathrm{2}{x}\: \\ $$$$\Leftrightarrow\:{y}'\:=\:−\mathrm{2}{x}\:{e}^{−{x}^{\mathrm{2}} } \\ $$$$\Leftrightarrow\frac{{dy}}{{dx}}=−\mathrm{2}{x}\:{e}^{−{x}^{\mathrm{2}} } \\ $$