Differentiate-y-sin-xy-

Question Number 161311 by CM last updated on 15/Dec/21

D i f f e r e n t i a t e y = \sin x y

Answered by mr W last updated on 15/Dec/21

\frac{d y}{d x} = \cos (x y) (y + x \frac{d y}{d x})

\Rightarrow \frac{d y}{d x} = \frac{y \cos (x y)}{1 - x \cos (x y)}

Commented by CM last updated on 16/Dec/21

T h a n k y o u s i r

Answered by 1549442205PVT last updated on 16/Dec/21

w e a s s u m e t h a t y i s a f u n c t i o n o f x . T h e n

y^{'} = c o s x y . (y + {x y}^{'}) \Rightarrow y^{'} (1 - x c o s x y) = y c o s x y

\Rightarrow y^{'} = \frac{y c o s x y}{1 - x c o s x y}