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draw-the-graph-of-f-x-1-x-2-for-0-x-1-




Question Number 56179 by problem solverd last updated on 11/Mar/19
draw the graph of  f(x)=(√(1−x^2 ))  for 0≤x≤1
drawthegraphoff(x)=1x2for0x1
Commented by mr W last updated on 12/Mar/19
y=(√(1−x^2 ))  ⇒x^2 +y^2 =1^2   the graph is just a part of a circle with  radius 1.
y=1x2x2+y2=12thegraphisjustapartofacirclewithradius1.
Answered by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19
with the use of graphical app you can see the  graph..  trying to solve...  f(0)=1  f(1)=0  (df/dx)=(1/(2(√(1−x^2 ))))×−2x=((−x)/( (√(1−x^2 ))))  (d^2 f/dx^2 )=−1×{(((√(1−x^2 )) ×(dx/dx)−x×(d/dx)((√(1−x^2 )) ) )/(1−x^2 ))}  (d^2 f/dx^2 )=−1×{(((√(1−x^2 )) −x×(1/(2(√(1−x^2 )) ))×−2x)/(1−x^2 ))}  =−1×{(((√(1−x^2 )) +(x^2 /( (√(1−x^2  )))))/((1−x^2 )))}  =((−1)/((1−x^2 )^(3/2) ))  (d^2 f/dx^2 )<0  in x [0,1]  now   if (d^2 f/dx^2 )>0  hold water that means concave up  if (d^2 f/dx^2 )<0  spill water that means cocave down  that means CONVEX  so in x[0,1]  shape of f(x) is convex  ..
withtheuseofgraphicalappyoucanseethegraph..tryingtosolvef(0)=1f(1)=0dfdx=121x2×2x=x1x2d2fdx2=1×{1x2×dxdxx×ddx(1x2)1x2}d2fdx2=1×{1x2x×121x2×2x1x2}=1×{1x2+x21x2(1x2)}=1(1x2)32d2fdx2<0inx[0,1]nowifd2fdx2>0holdwaterthatmeansconcaveupifd2fdx2<0spillwaterthatmeanscocavedownthatmeansCONVEXsoinx[0,1]shapeoff(x)isconvex..
Commented by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19
Commented by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19

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