Question Number 56179 by problem solverd last updated on 11/Mar/19

Commented by mr W last updated on 12/Mar/19

Answered by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19
![with the use of graphical app you can see the graph.. trying to solve... f(0)=1 f(1)=0 (df/dx)=(1/(2(√(1−x^2 ))))×−2x=((−x)/( (√(1−x^2 )))) (d^2 f/dx^2 )=−1×{(((√(1−x^2 )) ×(dx/dx)−x×(d/dx)((√(1−x^2 )) ) )/(1−x^2 ))} (d^2 f/dx^2 )=−1×{(((√(1−x^2 )) −x×(1/(2(√(1−x^2 )) ))×−2x)/(1−x^2 ))} =−1×{(((√(1−x^2 )) +(x^2 /( (√(1−x^2 )))))/((1−x^2 )))} =((−1)/((1−x^2 )^(3/2) )) (d^2 f/dx^2 )<0 in x [0,1] now if (d^2 f/dx^2 )>0 hold water that means concave up if (d^2 f/dx^2 )<0 spill water that means cocave down that means CONVEX so in x[0,1] shape of f(x) is convex ..](https://www.tinkutara.com/question/Q56194.png)
Commented by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19

Commented by tanmay.chaudhury50@gmail.com last updated on 11/Mar/19
