Menu Close

Draw-the-graph-of-the-function-f-g-x-if-f-g-R-R-are-given-by-f-x-2x-1-g-x-x-1-Find-the-domain-and-the-range-of-f-g-x-




Question Number 24821 by NECx last updated on 26/Nov/17
Draw the graph of the function  ((f/g))(x) if f,g:R→R are given by  f(x)=2x−1,g(x)=x+1.Find the  domain and the range of ((f/g))(x)
$${Draw}\:{the}\:{graph}\:{of}\:{the}\:{function} \\ $$$$\left(\frac{{f}}{{g}}\right)\left({x}\right)\:{if}\:{f},{g}:\mathbb{R}\rightarrow\mathbb{R}\:{are}\:{given}\:{by} \\ $$$${f}\left({x}\right)=\mathrm{2}{x}−\mathrm{1},{g}\left({x}\right)={x}+\mathrm{1}.{Find}\:{the} \\ $$$${domain}\:{and}\:{the}\:{range}\:{of}\:\left(\frac{{f}}{{g}}\right)\left({x}\right) \\ $$$$ \\ $$
Answered by mrW1 last updated on 27/Nov/17
h(x)=((f(x))/(g(x)))=((2x−1)/(x+1))=((2x+2−3)/(x+1))=2−(3/(x+1))  Domain: x∈(−∞,−1) and (−1,+∞)  Range: (−∞,2) and (2,+∞)
$${h}\left({x}\right)=\frac{{f}\left({x}\right)}{{g}\left({x}\right)}=\frac{\mathrm{2}{x}−\mathrm{1}}{{x}+\mathrm{1}}=\frac{\mathrm{2}{x}+\mathrm{2}−\mathrm{3}}{{x}+\mathrm{1}}=\mathrm{2}−\frac{\mathrm{3}}{{x}+\mathrm{1}} \\ $$$${Domain}:\:{x}\in\left(−\infty,−\mathrm{1}\right)\:{and}\:\left(−\mathrm{1},+\infty\right) \\ $$$${Range}:\:\left(−\infty,\mathrm{2}\right)\:{and}\:\left(\mathrm{2},+\infty\right) \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *