Question Number 83893 by sahnaz last updated on 07/Mar/20
$$\int\frac{\mathrm{du}}{\mathrm{u}−\mathrm{u}^{\mathrm{2}} } \\ $$
Commented by abdomathmax last updated on 07/Mar/20
$$\int\:\:\frac{{du}}{{u}−{u}^{\mathrm{2}} }\:=\int\:\:\frac{{du}}{{u}\left(\mathrm{1}−{u}\right)}\:=\int\:\:\left(\frac{\mathrm{1}}{{u}}+\frac{\mathrm{1}}{\mathrm{1}−{u}}\right){du} \\ $$$$={ln}\mid\frac{{u}}{\mathrm{1}−{u}}\mid\:+{C} \\ $$