dx-1-x-10- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 164171 by mkam last updated on 15/Jan/22 ∫dx1+x10 Answered by Ar Brandon last updated on 15/Jan/22 ∫dx1+x10=∫∑∞n=0(−x10)ndx=∑n⩾0(1)n(−1)nx10n+1n!(10n+1)=x10∑n⩾0(1)n(−x10)nn!(n+110)=x10∑n⩾0(1)nΓ(n+110)n!Γ(n+1110)(−x10)n=x100∑n⩾0(1)n(110)nn!(1110)n(−x10)n=x1002F1(110,1;1110;−x10)+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: z-x-yi-C-z-x-y-C-proof-z-2-z-2-zz-so-z-0-1-z-z-z-2-Next Next post: Question-33100 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.