dx-1-x-7- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 158492 by bobhans last updated on 05/Nov/21 ∫dx1+x7? Answered by Ar Brandon last updated on 05/Nov/21 x7+1=0⇒x7=e(2k+1)iπ⇒xk=e(2k+17)iπ,k∈[0,6]k∈ZI=∫dxx7+1=∫dx∏6k=0(x−xk)=∫∑6k=0akx−xkdx,ak=17xk6=−xk7I=−17∫∑6k=0xkx−xkdx=−17∑6k=0xkln∣x−xk∣+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: pls-help-find-x-0-5-x-0-25-find-x-Next Next post: sin-2-x-dx-1-cos-x-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.