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dx-1-x-7-




Question Number 158492 by bobhans last updated on 05/Nov/21
 ∫ (dx/(1+x^7 )) ?
dx1+x7?
Answered by Ar Brandon last updated on 05/Nov/21
x^7 +1=0⇒x^7 =e^((2k+1)iπ) ⇒x_k =e^((((2k+1)/7))iπ) , k∈[0, 6] k∈Z  I=∫(dx/(x^7 +1))=∫(dx/(Π_(k=0) ^6 (x−x_k )))=∫Σ_(k=0) ^6 (a_k /(x−x_k ))dx , a_k =(1/(7x_k ^6 ))=−(x_k /7)  I=−(1/7)∫Σ_(k=0) ^6 (x_k /(x−x_k ))dx=−(1/7)Σ_(k=0) ^6 x_k ln∣x−x_k ∣+C
x7+1=0x7=e(2k+1)iπxk=e(2k+17)iπ,k[0,6]kZI=dxx7+1=dx6k=0(xxk)=6k=0akxxkdx,ak=17xk6=xk7I=176k=0xkxxkdx=176k=0xklnxxk+C

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