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dx-2x-3-2-3-




Question Number 88097 by sahnaz last updated on 08/Apr/20
∫(dx/((2x−3)^(2/3) ))
$$\int\frac{\mathrm{dx}}{\left(\mathrm{2x}−\mathrm{3}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} } \\ $$
Answered by john santu last updated on 08/Apr/20
∫ t^(−2/3) ×(1/2)dt   [ t = 2x−3 ]  = (1/2)×3 × (t)^(1/(3  ))  + c   = (3/2)((2x−3))^(1/(3   ))  + c
$$\int\:{t}^{−\mathrm{2}/\mathrm{3}} ×\frac{\mathrm{1}}{\mathrm{2}}{dt}\:\:\:\left[\:{t}\:=\:\mathrm{2}{x}−\mathrm{3}\:\right] \\ $$$$=\:\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}\:×\:\sqrt[{\mathrm{3}\:\:}]{{t}}\:+\:{c}\: \\ $$$$=\:\frac{\mathrm{3}}{\mathrm{2}}\sqrt[{\mathrm{3}\:\:\:}]{\mathrm{2}{x}−\mathrm{3}}\:+\:{c}\: \\ $$

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