dx-5-4x-2x-2- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 86080 by ar247 last updated on 27/Mar/20 ∫dx5−4x−2x2 Commented by ar247 last updated on 27/Mar/20 anyonecanhelpmeplease? Answered by Rio Michael last updated on 27/Mar/20 5−4x−2x2=(52−2x−x2)2=(52−1+(1−x)2)2=(32+(1−x)2)2let1−x=u⇒−du=dx∫dx5−4x−2x2=−12∫du32+u2=−12arsinh(2x3)+k Commented by ar247 last updated on 27/Mar/20 anythingelese? Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-e-x-x-ln-x-dx-Next Next post: let-f-x-x-1-x-2-and-3-4-solve-in-R-f-f-f-x-0- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.