dx-5e-2x-4e-x-1- Tinku Tara June 4, 2023 Differentiation 0 Comments FacebookTweetPin Question Number 102461 by bemath last updated on 09/Jul/20 ∫dx5e2x+4ex+1=? Answered by PRITHWISH SEN 2 last updated on 09/Jul/20 ∫dxex1e2x+4ex+5put1ex=t⇒dxex=−dt=−∫dtt2+4t+5=−∫dt(t+2)2+1=−ln∣(t+2)+t2+4t+5∣+C=ln∣ex2ex+1+5e2x+4ex+1∣+Cpleasecheck. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: calculate-lim-n-1-2i-1-it-n-n-1-it-n-n-Next Next post: let-f-x-e-x-2-1-prove-that-f-n-x-p-n-x-e-x-2-with-p-n-is-a-polynom-2-find-a-relation-of-recurrence-between-the-p-n-3-calculate-p-1-p-2-p-3-p-4- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.