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dx-dy-a-b-a-y-c-b-a-sin-2piy-c-2pi-for-a-gt-0-b-gt-0-c-gt-0-on-x-0-

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Question Number 130087 by bobhans last updated on 22/Jan/21
(dx/dy) = a + (((b−a)y)/c) + (((b−a)sin (((2πy)/c)))/(2π)) for a>0 , b>0, c>0 on x≥0
dxdy=a+(b−a)yc+(b−a)sin(2πyc)2πfora>0,b>0,c>0onx⩾0
Answered by benjo_mathlover last updated on 22/Jan/21
dx = a dy + (((b−a))/c) y dy + ((b−a)/(2π)) sin (((2πy)/c)) dy x= ay +(((b−a)y^2 )/(2c)) −(((b−a)c)/(4π^2 )) cos (((2πy)/c)) + λ
dx=ady+(b−a)cydy+b−a2πsin(2πyc)dyx=ay+(b−a)y22c−(b−a)c4π2cos(2πyc)+λ

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