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dx-sin-4-x-cos-4-x-




Question Number 20468 by tammi last updated on 27/Aug/17
∫(dx/(sin^4 x−cos^4 x))
dxsin4xcos4x
Answered by ajfour last updated on 27/Aug/17
−∫sec 2xdx=−(1/2)ln ∣sec 2x+tan 2x∣+C .
sec2xdx=12lnsec2x+tan2x+C.

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