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dx-sinx-sin-x-




Question Number 44148 by LXZ last updated on 22/Sep/18
∫dx/sinx∙sin(x+α)=?
dx/sinxsin(x+α)=?
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Sep/18
∫(dx/(sinx.sin(x+α)))  (1/(sinα))∫((sin{(x+α)−x})/(sinx.sin(x+α)))dx  (1/(sinα))∫((sin(x+α)cosx−cos(x+α)sinx)/(sinxsin(x+α)))dx  (1/(sinα))[∫cotx−cot(x+α)]dx  (1/(sinα))[lnsinx−lnsin(x+α)]  (1/(sinα))ln{((sinx)/(sin(x+α)))}+c
dxsinx.sin(x+α)1sinαsin{(x+α)x}sinx.sin(x+α)dx1sinαsin(x+α)cosxcos(x+α)sinxsinxsin(x+α)dx1sinα[cotxcot(x+α)]dx1sinα[lnsinxlnsin(x+α)]1sinαln{sinxsin(x+α)}+c

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