dx-tan-x-sin-x- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 113757 by bemath last updated on 15/Sep/20 ∫dxtanx−sinx? Answered by bemath last updated on 15/Sep/20 Answered by Dwaipayan Shikari last updated on 15/Sep/20 2∫12t1−t2−2t1+t2.11+t2dttanx2=t2∫12t(1+t2−1+t2(1−t2)(1+t2)).11+t2dt∫1−t22t3dt=−14t2−12logt+C=−14tan2x2−12log(tanx2)+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Solve-for-x-a-ax-1-b-bx-1-a-b-x-1-a-1-b-Next Next post: 0-1-log-x-1-x-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.