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dx-tan-x-sin-x-




Question Number 113757 by bemath last updated on 15/Sep/20
 ∫ (dx/(tan x−sin x)) ?
dxtanxsinx?
Answered by bemath last updated on 15/Sep/20
Answered by Dwaipayan Shikari last updated on 15/Sep/20
2∫(1/(((2t)/(1−t^2 ))−((2t)/(1+t^2 )))).(1/(1+t^2 ))dt                 tan(x/2)=t     2∫(1/(2t(((1+t^2 −1+t^2 )/((1−t^2 )(1+t^2 )))))).(1/(1+t^2 ))dt  ∫((1−t^2 )/(2t^3 ))dt=−(1/(4t^2 ))−(1/2)logt+C=−(1/(4tan^2 (x/2)))−(1/2)log(tan(x/2))+C
212t1t22t1+t2.11+t2dttanx2=t212t(1+t21+t2(1t2)(1+t2)).11+t2dt1t22t3dt=14t212logt+C=14tan2x212log(tanx2)+C

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