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dx-x-1-3-4x-




Question Number 124624 by bemath last updated on 04/Dec/20
 ∫ (dx/( (x)^(1/3)  +4x))
dxx3+4x
Answered by Dwaipayan Shikari last updated on 04/Dec/20
∫((3u^2 du)/(u+4u^3 ))=(3/8)∫((8udu)/(1+4u^2 ))=(3/8)log(1+4u^2 )=(3/8)log(1+4x^(2/3) )+C  Taking (x=u^3 )
3u2duu+4u3=388udu1+4u2=38log(1+4u2)=38log(1+4x23)+CTaking(x=u3)

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