dx-x-x-1-4-1-10- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 79612 by john santu last updated on 26/Jan/20 ∫dxx(x4+1)10=? Answered by MJS last updated on 26/Jan/20 ∫dxx12(x14+1)10=[t=x14→dx=4x34dt]=4∫t(t+1)10dt=4∫dt(t+1)9−4∫dt(t+1)10==−12(t+1)8+49(t+1)9=−9t+118(t+1)9==−9x14+118(x14+1)9+C Commented by peter frank last updated on 26/Jan/20 thanks Commented by john santu last updated on 27/Jan/20 thankyoumister Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-14073Next Next post: Question-14078 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.