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e-ax-b-dx-




Question Number 102043 by Dwaipayan Shikari last updated on 06/Jul/20
∫e^(√(ax+b)) dx
eax+bdx
Commented by Dwaipayan Shikari last updated on 06/Jul/20
(2/a)∫e^u udu             {suppose ax+b=u^2   (2/a)ue^u −(2/a)e^u =(2/a)e^(√(ax+b)) ((√(ax+b))−1)
2aeuudu{supposeax+b=u22aueu2aeu=2aeax+b(ax+b1)

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