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e-e-e-1-3-e-1-4-e-1-5-e-1-6-e-1-7-e-1-8-




Question Number 88360 by jagoll last updated on 10/Apr/20
(e/( (√e))) × ((e)^(1/(3  )) /( (e)^(1/(4  )) )) × ((e)^(1/(5  )) /( (e)^(1/(6  )) )) × ((e)^(1/(7  )) /( (e)^(1/(8  )) ))×...=?
ee×e3e4×e5e6×e7e8×=?
Commented by john santu last updated on 10/Apr/20
= e^(1−(1/2)+(1/3)−(1/4)+(1/5)−(1/6)+...)   [ ln (1+x) = x−(x^2 /2)+(x^3 /3)−(x^4 /4)+... ]  −1 < x ≤ 1 , ln (2) = 1−(1/2)+(1/3)−(1/4)+... ]  ⇒= e^(ln (2))  = 2.
=e112+1314+1516+[ln(1+x)=xx22+x33x44+]1<x1,ln(2)=112+1314+]⇒=eln(2)=2.
Commented by jagoll last updated on 10/Apr/20
thank you
thankyou

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