e-e-sin-x-sec-2-x-1-dx-

Question Number 192289 by cortano12 last updated on 14/May/23

\underset{- e}{\int^{e}} \frac{\sin x}{\sec^{2} x + 1} dx = ?

Answered by mehdee42 last updated on 14/May/23

f (x) = \frac{s i n x}{{s e c x}^{2} x + 1} \Rightarrow f (- x) = f (x)

\Rightarrow \int_{- e}^{e} \frac{s i n x}{{s e c}^{2} x + 1} d x = 0

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