e-pi-1-e-pi-1-pi-2-pi-2-6-pi-2-10-pi-2-14-

Tinku Tara June 4, 2023 Others 0 Comments

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Question Number 126704 by Dwaipayan Shikari last updated on 23/Dec/20

((e^π −1)/(e^π +1))=(π/(2+(π^2 /(6+(π^2 /(10+(π^2 /(14+....))))))))

\frac{e^{π} - 1}{e^{π} + 1} = \frac{π}{2 + \frac{π^{2}}{6 + \frac{π^{2}}{10 + \frac{π^{2}}{14 + \dots .}}}}

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