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e-x-dx-




Question Number 90023 by Rio Michael last updated on 20/Apr/20
 ∫ e^(∣x∣)  dx = ???
exdx=???
Answered by MJS last updated on 21/Apr/20
e^(∣x∣) = { ((e^(−x) ; x<0)),((e^x ; x≥0)) :} ⇒ ∫e^(∣x∣) dx= { ((−e^(−x) +C; x<0)),((e^x +C; x≥0)) :}
ex={ex;x<0ex;x0exdx={ex+C;x<0ex+C;x0

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