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e-x-logx-




Question Number 115696 by Dwaipayan Shikari last updated on 27/Sep/20
e^x =logx
ex=logx
Commented by Dwaipayan Shikari last updated on 27/Sep/20
e^x =logx  e^e^x  =x  e^e^e^e^d^d^d      =x  e^x =x  x=logx  e^(−logx) =(1/(logx))  −logxe^(−logx) =−  −logx=W_0 (−1)  x=e^(−W_0 (−1))    (Complex solution x∈C)  Error!  e^x =logx  And e^x =x   (dosen′t satisfy any condition)
ex=logxeex=xeeeeddd=xex=xx=logxelogx=1logxlogxelogx=logx=W0(1)x=eW0(1)(ComplexsolutionxC)Error!ex=logxAndex=x(dosentsatisfyanycondition)
Commented by TANMAY PANACEA last updated on 27/Sep/20
from graph it is clear that e^x  and lnx never cross  each other ...so no solution
fromgraphitisclearthatexandlnxnevercrosseachothersonosolution
Commented by Dwaipayan Shikari last updated on 27/Sep/20
Complex solution   No real solution
ComplexsolutionNorealsolution
Commented by TANMAY PANACEA last updated on 27/Sep/20
ok
ok

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