e-z-1-f-1-a-b-z-b-b-a-G-1-2-1-1-z-0-1-b-a-b-1-

Question Number 88417 by M±th+et£s last updated on 10/Apr/20

e^{- z}_{1} f_{1} (a; b; z) = \frac{Γ (b)}{Γ (b - a)} G_{1, 2}^{1, 1} (z ∣_{0, 1 - b}^{a - b + 1})

Commented by M±th+et£s last updated on 10/Apr/20

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