Equilibrate-it-using-oxydation-s-number-NH-4-2-Cr-2-O-7-N-2-H-2-O-Cr-2-O-7-

Question Number 99133 by mathocean1 last updated on 18/Jun/20

$${Equilibrate}\:{it}\:{using}\:{oxydation}'{s} \\ $$$${number} \\ $$$$\left({NH}_{\mathrm{4}} \right)_{\mathrm{2}} {Cr}_{\mathrm{2}} {O}_{\mathrm{7}} \rightarrow{N}_{\mathrm{2}} +{H}_{\mathrm{2}} {O}+{Cr}_{\mathrm{2}\:\:} {O}_{\mathrm{7}} \\ $$

Terms of Service
Privacy Policy
Contact: info@tinkutara.com