Equilibrate-it-using-oxydation-s-number-NH-4-2-Cr-2-O-7-N-2-H-2-O-Cr-2-O-7-

Question Number 99133 by mathocean1 last updated on 18/Jun/20

E q u i l i b r a t e i t u s i n g {o x y d a t i o n}^{'} s

n u m b e r

{({N H}_{4})}_{2} {C r}_{2} O_{7} \to N_{2} + H_{2} O + {C r}_{2} O_{7}