Evaluate-0-1-2-x-dx-

Question Number 192452 by Spillover last updated on 18/May/23

E v a l u a t e \int_{0}^{1} 2^{x} d x

Answered by senestro last updated on 18/May/23

1 / \ln 2

Commented by Spillover last updated on 18/May/23

s h o w y o u r s o l u t i o n

Answered by manxsol last updated on 19/May/23

y = 2^{x}

l n y = x l n 2

\frac{d y}{y} = l n 2 d x

x = 0 y = 1

x = 1 y = 2

\int_{1}^{2} y \frac{d y}{y l n 2} = \frac{y}{l n 2} ∣_{1}^{2} = \frac{2}{l n 2} - \frac{1}{l n 2} = \frac{1}{l n 2}

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