Evaluate-1-1-1-x-1-dx-

Question Number 87862 by Rio Michael last updated on 06/Apr/20

Evaluate {\int^{1}}_{- 1} \frac{1}{x - 1} d x

Commented by MJS last updated on 06/Apr/20

{doesn}^{'} t exist

\int \frac{d x}{x - 1} = \ln ∣ x - 1 ∣ + C

but \lim_{x \to 1} \ln ∣ x - 1 ∣ = - \infty

Commented by Rio Michael last updated on 06/Apr/20

so sir can we say the integral diverges ?

Commented by MJS last updated on 07/Apr/20

yes

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