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evaluate-2x-4x-5-dx-




Question Number 158768 by EbrimaDanjo last updated on 08/Nov/21
  evaluate  ∫2x(√(4x−5)) dx
evaluate2x4x5dx
Answered by MJS_new last updated on 08/Nov/21
∫2x(√(4x−5))dx=?  without substitution:  (d/dx)[(ax+b)(4x−5)^(3/2) ]=(10ax−5a+6b)(√(4x−5))  ⇒  10ax−5a+6b=2x  ⇒  a=(1/5)∧b=(1/6)  ⇒  ∫2x(√(4x−5))dx=((x/5)+(1/6))(4x−5)^(3/2) +C
2x4x5dx=?withoutsubstitution:ddx[(ax+b)(4x5)3/2]=(10ax5a+6b)4x510ax5a+6b=2xa=15b=162x4x5dx=(x5+16)(4x5)3/2+C
Commented by EbrimaDanjo last updated on 08/Nov/21
thanks sir
thankssir

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