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Evaluate-cos-20-cos-40-cos-80-This-question-is-just-for-fun-and-practice-Evryone-who-wants-can-answer-this-question-




Question Number 17983 by alex041103 last updated on 13/Jul/17
Evaluate cos(20°)cos(40°)cos(80°).  This question is just for fun and practice.  Evryone who wants can answer this question.
Evaluatecos(20°)cos(40°)cos(80°).Thisquestionisjustforfunandpractice.Evryonewhowantscananswerthisquestion.
Answered by ajfour last updated on 13/Jul/17
cos 20°cos 40°cos 80°=    (1/(2sin 20°))[2sin 20°cos 20°]cos 40°cos 80°  =(1/(4sin 20°))[2sin 40°cos 40°]cos 80°  =(1/(8sin 20°))[2sin 80°cos 80°]  = ((sin (180°−20°))/(8sin 20°)) =(1/8) .
cos20°cos40°cos80°=12sin20°[2sin20°cos20°]cos40°cos80°=14sin20°[2sin40°cos40°]cos80°=18sin20°[2sin80°cos80°]=sin(180°20°)8sin20°=18.
Commented by alex041103 last updated on 13/Jul/17
well done sir
welldonesir
Commented by alex041103 last updated on 13/Jul/17
if you want you can try Q.17525
ifyouwantyoucantryQ.17525

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