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Evaluate-d-2-y-dx-2-when-x-ln-2-and-y-2-




Question Number 160606 by ZiYangLee last updated on 03/Dec/21
Evaluate (d^2 y/dx^2 ) when x=ln 2 and y=2.
Evaluated2ydx2whenx=ln2andy=2.
Commented by MJS_new last updated on 03/Dec/21
y=f(x)  (dy/dx)=f ′(x)  (d^2 y/dx^2 )=f ′′(x)  if y=2 ⇔ f(x)=2 ⇒ f(ln 2)=2  f(x)=2 ⇒ f ′(x)=0 ⇒ f ′′(x)=0 ⇔ (d^2 y/dx^2 )=0
y=f(x)dydx=f(x)d2ydx2=f(x)ify=2f(x)=2f(ln2)=2f(x)=2f(x)=0f(x)=0d2ydx2=0

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