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evaluate-I-0-1-x-1-x-x-dx-




Question Number 119832 by talminator2856791 last updated on 27/Oct/20
              evaluate:    I  = ∫_0 ^( 1) (((x+1)/x))^(x!) dx
$$\: \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\mathrm{evaluate}:\:\:\:\:{I}\:\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \left(\frac{{x}+\mathrm{1}}{{x}}\right)^{{x}!} {dx} \\ $$$$ \\ $$$$ \\ $$

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