Evaluate-log-x-a-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 96672 by 175 last updated on 03/Jun/20 Evaluate:∫logxaxdx Commented by bemath last updated on 03/Jun/20 ∫ln(a)xln(x)dx=ln(a)∫duu=ln(a)ln(u)+c=ln(a)ln(ln(x))+c Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-31133Next Next post: Question-162209 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.