Menu Close

Evaluate-the-Integral-0-x-2-1-1-x-dx-Z-A-




Question Number 164854 by Zaynal last updated on 22/Jan/22
                         Evaluate the Integral;                            [∫_0 ^∞  ((x^2  − 1)/(1−x)) dx =??]            ^({Z.A})
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{Evaluate}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{Integral}}; \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\int_{\mathrm{0}} ^{\infty} \:\frac{\boldsymbol{{x}}^{\mathrm{2}} \:−\:\mathrm{1}}{\mathrm{1}−\boldsymbol{{x}}}\:\boldsymbol{{dx}}\:=??\right] \\ $$$$\:\:\:\:\:\:\:\:\:\:\:^{\left\{\boldsymbol{{Z}}.\mathrm{A}\right\}} \\ $$
Answered by MJS_new last updated on 22/Jan/22
lim_(x→1)  ((x^2 −1)/(1−x)) =−2 ⇒ ∫((x^2 −1)/(1−x))dx=−∫(x+1)dx  ⇒ ∫_0 ^∞ ((x^2 −1)/(1−x))dx doesn′t converge
$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{1}−{x}}\:=−\mathrm{2}\:\Rightarrow\:\int\frac{{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{1}−{x}}{dx}=−\int\left({x}+\mathrm{1}\right){dx} \\ $$$$\Rightarrow\:\underset{\mathrm{0}} {\overset{\infty} {\int}}\frac{{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{1}−{x}}{dx}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{converge} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *