evaluate-x-i-dx-where-i-1-

Question Number 41108 by mondodotto@gmail.com last updated on 02/Aug/18

evaluate \int x^{i} d x

where i = \sqrt{- 1}

Answered by MJS last updated on 02/Aug/18

\int x^{z} d x = \frac{1}{z + 1} x^{z + 1}

\int x^{i} d x = \frac{1}{1 + i} x^{1 + i} = (\frac{1}{2} - \frac{1}{2} i) x^{1 + i}

Facebook Tweet Pin