Menu Close

Exercise-ABC-is-a-triangle-AB-AC-2-and-BC-2-2-I-is-midle-of-BC-J-is-a-point-such-as-AJ-2-3-AI-J-is-the-center-of-gravity-of-the-triangle-1-a-we-define-the-set-T-of-point-M




Question Number 97174 by mathocean1 last updated on 06/Jun/20
Exercise_(−)   ABC is a triangle. AB=AC=2 and  BC=2(√2). I is midle of [BC].  J is a point such as AJ^(→) =(2/3)AI^(→) . J is  the center of gravity of the triangle.  1)a) we define the set(T) of ∀ point M  of plane:  AM^2 +BM^2 +CM^2 =8.  Show that BM^2 +CM^2 =2IM^2 +4  and AM^2 +2IM^2 =3JM^2 +(4/3)  b)deduct that   AM^2 +BM^2 +CM^2 =3JM^2 +((16)/3)  c)Deduct the nature of (T)
ExerciseABCisatriangle.AB=AC=2andBC=22.Iismidleof[BC].JisapointsuchasAJ=23AI.Jisthecenterofgravityofthetriangle.1)a)wedefinetheset(T)ofpointMofplane:AM2+BM2+CM2=8.ShowthatBM2+CM2=2IM2+4andAM2+2IM2=3JM2+43b)deductthatAM2+BM2+CM2=3JM2+163c)Deductthenatureof(T)

Leave a Reply

Your email address will not be published. Required fields are marked *