express-4t-2-28-t-4-t-2-6-as-a-partial-fraction- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 33899 by mondodotto@gmail.com last updated on 27/Apr/18 express4t2−28t4+t2−6asapartialfraction. Answered by MJS last updated on 27/Apr/18 t4+t2−6=0t2=−12±14+6=−12±52=−3∨2t4+t2−6=(t2+3)(t2−2)4t2−28t4+t2−6=At2+3+Bt2−2=A(t2−2)+B(t2+3)t4+t2−6(A+B)t2+(−2A+3B)=4t2−28A+B=4∧−2A+3B=−28A=4−B−2(4−B)+3B=−28B=−4A=84t2−28t4+t2−6=8t2+3−4t2−2 Commented by math1967 last updated on 27/Apr/18 IcanalsowriteA(t2−2)+B(t2+3)=4t2−28puttingt2=2A×0+B×5=4×2−28∴B=−4similarlywegetA=8 Answered by math1967 last updated on 27/Apr/18 8(t2−2)−4(t2+3)(t2−2)(t2+3)8t2+3−4t2−2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: let-consider-x-x-x-1-prove-that-a-gt-0-0-1-a-x-dx-ln-a-2-prove-that-n-N-0-1-x-sin-2pinx-dx-pi-2-Next Next post: Question-164973 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.